0.0146x^2+1x-2=0

Solution for 0.0146x^2+1x-2=0 equation:

0.0146x^2+1x-2=0

We add all the numbers together, and all the variables

0.0146x^2+x-2=0

a = 0.0146; b = 1; c = -2;
Δ = b2-4ac
Δ = 12-4·0.0146·(-2)
Δ = 1.1168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1.1168}}{2*0.0146}=\frac{-1-\sqrt{1.1168}}{0.0292}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1.1168}}{2*0.0146}=\frac{-1+\sqrt{1.1168}}{0.0292}
$